如何检查用户是否具有特定角色？

如果仅当前用户需要此 current_user_can() 既接受角色也接受能力

更新:不再保证将角色名称传递给current_user_can()(请参见#22624 ).相反,您可能希望检查用户角色:

 $user = wp_get_current_user();
if ( in_array( 'author', (array) $user->roles ) ) {
    //The user has the "author" role
}
 

If you only need this for current user current_user_can() accepts both roles and capabilities.

UPDATE: Passing a role name to current_user_can() is no longer guaranteed to work correctly (see #22624). Instead, you may wish to check user role:

$user = wp_get_current_user();
if ( in_array( 'author', (array) $user->roles ) ) {
    //The user has the "author" role
}

我一直在寻找一种使用用户ID来获取用户角色的方法.这是我想出的:

 function get_user_roles_by_user_id( $user_id ) {
    $user = get_userdata( $user_id );
    return empty( $user ) ? array() : $user->roles;
}
 

然后,可以像这样实现is_user_in_role()函数:

 function is_user_in_role( $user_id, $role  ) {
    return in_array( $role, get_user_roles_by_user_id( $user_id ) );
}
 

I was looking for a way to get a user's role using the user's id. Here is what I came up with:

function get_user_roles_by_user_id( $user_id ) {
    $user = get_userdata( $user_id );
    return empty( $user ) ? array() : $user->roles;
}

Then, an is_user_in_role() function could be implemented like so:

function is_user_in_role( $user_id, $role  ) {
    return in_array( $role, get_user_roles_by_user_id( $user_id ) );
}

您也可以只创建一个新的用户对象:

 $user = new WP_User( $user_id );

if ( ! empty( $user->roles ) && is_array( $user->roles ) && in_array( 'Some_role', $user->roles ) ) {
    return true;
}
 

不确定删除了哪个版本的get_user_roles_by_user_id,但该功能不再可用.

You can also just create a new user object:

$user = new WP_User( $user_id );

if ( ! empty( $user->roles ) && is_array( $user->roles ) && in_array( 'Some_role', $user->roles ) ) {
    return true;
}

Not sure what version get_user_roles_by_user_id was removed in, but it's no longer an available function.

这是一个接受用户和角色以提高灵活性的功能:

函数my_has_role($ user,$ role){
  $ roles=$ user-> roles;
  返回in_array($ role,(array)$ user-> roles);
}

if(my_has_role($ user,'some_role')){
//做东西
}

Here is a function that accepts a user and role for greater flexibility:

function my_has_role($user, $role) {
  $roles = $user->roles; 
  return in_array($role, (array) $user->roles);
}

if(my_has_role($user, 'some_role')) {
  //do stuff
}

用户对象$user->roles上的调用角色不会返回所有角色.以下是查找用户是否具有角色或能力的正确方法.(这在wp 2.0.0及更高版本中有效.)以下函数与用户ID配合使用,您可以通过$current_user_id = get_current_user_id();

 /**
 * Returns true if a user_id has a given role or capability
 * 
 * @param int $user_id
 * @param string $role_or_cap Role or Capability
 * 
 * @return boolean
 */
function my_has_role($user_id, $role_or_cap) {

    $u = new \WP_User( $user_id );
    //$u->roles Wrong way to do it as in the accepted answer.
    $roles_and_caps = $u->get_role_caps(); //Correct way to do it as wp do multiple checks to fetch all roles

    if( isset ( $roles_and_caps[$role_or_cap] ) and $roles_and_caps[$role_or_cap] === true ) 
       {
           return true;
       }
 }
 

Calling roles on User Object $user->roles do not return all the roles. The correct way to find if the user has a role or capability is following. (This works in wp version 2.0.0 and greater.) The following function works with user id you can get the current user id by $current_user_id = get_current_user_id();

/**
 * Returns true if a user_id has a given role or capability
 * 
 * @param int $user_id
 * @param string $role_or_cap Role or Capability
 * 
 * @return boolean
 */
function my_has_role($user_id, $role_or_cap) {

    $u = new \WP_User( $user_id );
    //$u->roles Wrong way to do it as in the accepted answer.
    $roles_and_caps = $u->get_role_caps(); //Correct way to do it as wp do multiple checks to fetch all roles

    if( isset ( $roles_and_caps[$role_or_cap] ) and $roles_and_caps[$role_or_cap] === true ) 
       {
           return true;
       }
 }

这是旧文章,但这是一个通用功能,适用于所有WordPress版本.

 if(!function_exists('is_user')):
    function is_user ($role=NULL, $user_id=NULL)
    {
        if(empty($user_id)){
            $user = wp_get_current_user();
        } else {
            if(is_numeric($user_id) && $user_id == (int)$user_id) {
                $user = get_user_by('id', (int)$user_id);
            } else if(is_string($user_id) && $email = sanitize_email($user_id)) {
                $user = get_user_by('email', $email);
            } else {
                return false;
            }
        }
        
        if(!$user) return false;
        
        return in_array( $role, (array)$user->roles, true ) !== false;
    }
endif;
 

使用此功能,您可以按角色或用户ID/电子邮件搜索已登录的用户.还接受用户角色数组.

This is old post but here is one universal function what working on the all WordPress versions.

if(!function_exists('is_user')):
    function is_user ($role=NULL, $user_id=NULL)
    {
        if(empty($user_id)){
            $user = wp_get_current_user();
        } else {
            if(is_numeric($user_id) && $user_id == (int)$user_id) {
                $user = get_user_by('id', (int)$user_id);
            } else if(is_string($user_id) && $email = sanitize_email($user_id)) {
                $user = get_user_by('email', $email);
            } else {
                return false;
            }
        }
        
        if(!$user) return false;
        
        return in_array( $role, (array)$user->roles, true ) !== false;
    }
endif;

With this function you can search logged in user by role or by user ID/email. Also accept user roles array.