如果当前用户是管理员或编辑者

第一个答案,而不是与WordPress相关的,因为它只是PHP:使用逻辑"或"运算符:

 <?php if( current_user_can('editor') || current_user_can('administrator') ) {  ?>
    // Stuff here for administrators or editors
<?php } ?>
 

如果要检查两个以上的角色,则可以检查当前用户的角色是否在一系列角色中,例如:

 $user = wp_get_current_user();
$allowed_roles = array('editor', 'administrator', 'author');
<?php if( array_intersect($allowed_roles, $user->roles ) ) {  ?>
   // Stuff here for allowed roles
<?php } ?>
 

但是, current_user_can 不仅可以用于用户角色名称,还具有功能.

因此,一旦编辑者和管理员都可以编辑页面,则可以更轻松地检查这些功能:

 <?php if( current_user_can('edit_others_pages') ) {  ?>
    // Stuff here for user roles that can edit pages: editors and administrators
<?php } ?>
 

在此处中查看有关功能的更多信息.

First answer, not WordPress-related because it is just only PHP: Use the logic "OR" operator:

<?php if( current_user_can('editor') || current_user_can('administrator') ) {  ?>
    // Stuff here for administrators or editors
<?php } ?>

If you want to check more than two roles, you can check if the roles of the current user is inside an array of roles, something like:

$user = wp_get_current_user();
$allowed_roles = array('editor', 'administrator', 'author');
<?php if( array_intersect($allowed_roles, $user->roles ) ) {  ?>
   // Stuff here for allowed roles
<?php } ?>

However, current_user_can can be used not only with users' role name, but also with capabilities.

So, once both editors and administrators can edit pages, your life can be easier checking for those capabilities:

<?php if( current_user_can('edit_others_pages') ) {  ?>
    // Stuff here for user roles that can edit pages: editors and administrators
<?php } ?>

Have a look here for more information on capabilities.

首先,不应使用current_user_can()检查用户的角色-应该使用它检查用户是否具有特定的功能.

第二,您不必担心用户的角色,而是专注于功能,而不必费心做诸如原始问题(即检查用户是管理员还是其他用户)中的问题之类的事情.编辑).相反,如果按预期使用current_user_can()(用于检查用户的功能,而不是不),则不需要条件检查就可以包含"或"(||)测试.例如:

if ( current_user_can( 'edit_pages' ) ) { ...

edit_pages具有管理员和编辑者角色的功能,但不能具有任何较低的角色,例如作者.这就是打算使用current_user_can()的方式.

First, current_user_can() should not be used to check a user's role - it should be used to check if a user has a specific capability.

Second, rather than being concerned with the user's role but instead focusing on capabilities, you don't have to bother with doing things like the problem asked about in the original question (which is checking if the user is an administrator OR an editor). Instead, if current_user_can() was being used as intended, which is to check for a user's capabilities, not their role, you wouldn't need the conditional check to contain an "or" (||) test. For example:

if ( current_user_can( 'edit_pages' ) ) { ...

edit_pages is a capability of both administrator and editor roles, but not any lower roles such as authors. This is how current_user_can() was intended to be used.

正如@butlerblog回复所述,您不应使用current_user_can检查角色

此声明专门添加在has_cap函数的PHP文档中,该文档由current_user_can

虽然部分支持针对角色代替功能进行检查,但不鼓励这种做法,因为它可能会产生不可靠的结果.

正确 的方法是获取用户并检查$user->roles,如下所示:

 if( ! function_exists( 'current_user_has_role' ) ){
    function current_user_has_role( $role ) {

        $user = get_userdata( get_current_user_id() );
        if( ! $user || ! $user->roles ){
            return false;
        }

        if( is_array( $role ) ){
            return array_intersect( $role, (array) $user->roles ) ? true : false;
        }

        return in_array( $role, (array) $user->roles );
    }
}
 

以下是我用来执行此操作的一些辅助功能(因为有时我不想要当前用户):

 if( ! function_exists( 'current_user_has_role' ) ){
    function current_user_has_role( $role ){
        return user_has_role_by_user_id( get_current_user_id(), $role );
    }
}

if( ! function_exists( 'get_user_roles_by_user_id' ) ){
    function get_user_roles_by_user_id( $user_id ) {
        $user = get_userdata( $user_id );
        return empty( $user ) ? array() : $user->roles;
    }
}

if( ! function_exists( 'user_has_role_by_user_id' ) ){
    function user_has_role_by_user_id( $user_id, $role ) {

        $user_roles = get_user_roles_by_user_id( $user_id );

        if( is_array( $role ) ){
            return array_intersect( $role, $user_roles ) ? true : false;
        }

        return in_array( $role, $user_roles );
    }
}
 

然后您可以执行以下操作:

current_user_has_role( 'editor' );

或

current_user_has_role( array( 'editor', 'administrator' ) );

As @butlerblog reply stated, you should not use current_user_can to check against a role

This notice is specifically added in the PHP documentation of has_cap function which is called by current_user_can

While checking against a role in place of a capability is supported in part, this practice is discouraged as it may produce unreliable results.

The CORRECT way to do this is to get the user and check the $user->roles, like this:

if( ! function_exists( 'current_user_has_role' ) ){
    function current_user_has_role( $role ) {

        $user = get_userdata( get_current_user_id() );
        if( ! $user || ! $user->roles ){
            return false;
        }

        if( is_array( $role ) ){
            return array_intersect( $role, (array) $user->roles ) ? true : false;
        }

        return in_array( $role, (array) $user->roles );
    }
}

Here's some helper functions I use to do this (as sometimes i don't want just current user):

if( ! function_exists( 'current_user_has_role' ) ){
    function current_user_has_role( $role ){
        return user_has_role_by_user_id( get_current_user_id(), $role );
    }
}

if( ! function_exists( 'get_user_roles_by_user_id' ) ){
    function get_user_roles_by_user_id( $user_id ) {
        $user = get_userdata( $user_id );
        return empty( $user ) ? array() : $user->roles;
    }
}

if( ! function_exists( 'user_has_role_by_user_id' ) ){
    function user_has_role_by_user_id( $user_id, $role ) {

        $user_roles = get_user_roles_by_user_id( $user_id );

        if( is_array( $role ) ){
            return array_intersect( $role, $user_roles ) ? true : false;
        }

        return in_array( $role, $user_roles );
    }
}

Then you can just do this:

current_user_has_role( 'editor' );

or

current_user_has_role( array( 'editor', 'administrator' ) );

 <?php if( current_user_can('editor')) :
  echo "welcome";
elseif( current_user_can('member')) :
  echo "welcome";
else :
 wp_die("<h2>To view this page you must first <a href='". wp_login_url(get_permalink()) ."' title='Login'>log in</a></h2>");
endif;
?>
 

<?php if( current_user_can('editor')) :
  echo "welcome";
elseif( current_user_can('member')) :
  echo "welcome";
else :
 wp_die("<h2>To view this page you must first <a href='". wp_login_url(get_permalink()) ."' title='Login'>log in</a></h2>");
endif;
?>

上述解决方案问题的正确答案是通过其他方式进行编程:

 if( current_user_can('administrator')) { 

<!-- only administrator will see this message -->

} else { 

        if( wp_get_current_user('editor')) {

<!-- only editor but no administrator will see this message -->

?>
<style type="text/css">#perhapsDIVremovalidentifier{
display:none;
</style>
}
<?php
} else {

<!-- the user is neither editor or administrator -->

}}  
 

简述:找到了管理员,但是如果我们按下编辑器,也会找到管理员.因此,我们只允许管理员通过并仅标识编辑器.

请记住,您应该始终使用此代码在上面进行调用,以最大程度地减少cpu代码的使用:

 if(is_user_logged_in()){}
 

The correct answers to the above solution-question are by else programming basic:

if( current_user_can('administrator')) { 

<!-- only administrator will see this message -->

} else { 

        if( wp_get_current_user('editor')) {

<!-- only editor but no administrator will see this message -->

?>
<style type="text/css">#perhapsDIVremovalidentifier{
display:none;
</style>
}
<?php
} else {

<!-- the user is neither editor or administrator -->

}}  

Brief: The administrator is found, but if we push editor the administrator is as well found. So we just let the administrator pass through and identify the editor only.

Remember you should always use this code to call that above to minimize cpu code usage:

if(is_user_logged_in()){}