烘烤权上的“ estimated_time”不是常数
1 个回答
- 投票数
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- 2019-03-21
这种情况发生在网络运行迟了.
此
estimated_time
是根据"优先级为0的每个面包师都会烘焙"的假设计算的.每次由优先级为1的面包师烘烤一个块时,都会将其随后烘烤,并且随后的每个块都必须"稍后"烘烤...
感谢 @Pierre Boutillier 为此提供帮助
This happens when the network is running late.
This
estimated_time
is computed on the "every baker at priority 0 will bake" hypothesis.Each time a block is baked by the baker of priority 1, it is baked later and every following block has to be baked "later"...
Thanks to @Pierre Boutillier for helping with this
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谢谢.您能否提供一个指向该逻辑在何处实现的参考?Thank you. Could you please provide a pointer to where this logic is implemented as a reference ?
- 1
- 2019-03-21
- Ezy
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用链接更新了我的答案 https://tezos.gitlab.io/mainnet/api/odoc/_html/tezos-embedded-protocol-003-PsddFKi3/Tezos_embedded_raw_protocol_003_PsddFKi3/Delegate_services/Baking_rights/index.htmlUpdated my answer with a link https://tezos.gitlab.io/mainnet/api/odoc/_html/tezos-embedded-protocol-003-PsddFKi3/Tezos_embedded_raw_protocol_003_PsddFKi3/Delegate_services/Baking_rights/index.html
- 1
- 2019-03-21
- RoMarQ
昨天我注意到,烘焙权的
estimated_time
并不是恒定不变的.看起来它在每个块的开头都会发生变化.有人可以解释为什么会发生这种情况吗?
例如:
然后,在下一个块的开头: